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Yuyang

Wait, who wrote the 'share' in the Request table? Is it P2 or P1? If it is P1, how would this work for MESI protocol?

rokhinip

@yuyang, I do believe it makes sense that P1 wrote the 'share' in the request table. The fetching of data from memory is necessary for both processors anyways and presumably, each of them will change their state according to the 'status' on the request table, after receiving the data. I'm not a 100% sure if this is how it is in practice though.

rokhinip

I also just wanted to double check that in the event that the outgoing request is a write, then we always get a NACK and the only scenario where we do something other than a NACK is when we have 2 reads to the same location.

kayvonf

P1 made a note in it's own table that it is interesting in the result of the outstanding operation triggered by P2. 'Share' in this slide means, "I should take action when that response is put on the bus". Do not confuse it with the 'S' state in the coherence protocol. (However, it is true that this value will be loaded into P1's cache into the 'S' state, since the line will also be held by P2.)